The figure shows a circular wire - loop of radius a, carrying a current i, placed in a perpendicular magnetic field B. (a) Consider a small part dl of the wire. Find the force on this part of the wire exerted by the magnetic field. (b) Find the force of compression in the wire.
a) Fdl=i.(dl×B)=idlB
(because dl and B are perpendicular to each other)
(b) 2T sin θ=i.(dl×B)
2Tsinθ=idlB
∴θ is very small, sin θ=θ
dl=a×2θ
2Tθ=i.2a θ B
T=iaB