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Question

The figure shows a circular wire - loop of radius a, carrying a current i, placed in a perpendicular magnetic field B. (a) Consider a small part dl of the wire. Find the force on this part of the wire exerted by the magnetic field. (b) Find the force of compression in the wire.

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Solution

a) Fdl=i.(dl×B)=idlB

(because dl and B are perpendicular to each other)

(b) 2T sin θ=i.(dl×B)

2Tsinθ=idlB

θ is very small, sin θ=θ

dl=a×2θ

2Tθ=i.2a θ B

T=iaB






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