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Byju's Answer

Standard VII

Physics

Bernoulli's Principle

Figure 4.186 ...

Question

Figure 4.186 shows a liquid flowing through a tube at the rate of $0.1 m^{3} / s$ . The tube is branched into semicircular tubes of cross-sectional area $A / 3$ and $2 A / 3$ . The velocity of liquid at $Q$ is (the cross section of the main tube is $A = 10^{- 2} m^{2}$ and $v_{p} = 20 m / s)$

5 m / s

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30 m / s

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35 m / s

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None of these

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Solution

The correct option is A $5 m / s$
Total flow $Q_{p} + Q_{q}$ (Parallel Arrangement)
$0.1 = A_{p} . V_{p} + A_{q} . V_{q}$ $(Q = A V)$
$0.1 = \frac{A}{3} \times 20 + \frac{2 A}{3} \times V_{q}$
$0.1 = \frac{10^{- 2}}{3} \times 20 + \frac{2 \times 10^{- 2}}{3} \times V_{q}$
$∴ V_{q} = 5 m / s .$

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Figure 4.186 shows a liquid flowing through a tube at the rate of 0.1m3/s. The tube is branched into semicircular tubes of cross-sectional area A/3 and 2A/3. The velocity of liquid at Q is (the cross section of the main tube is A=10−2m2 and vp=20m/s)

The correct option is A 5 m/sTotal flow Qp+Qq (Parallel Arrangement)0.1=Ap.Vp+Aq.Vq (Q=AV)0.1=A3×20+2A3×Vq0.1=10−23×20+2×10−23×Vq∴Vq=5m/s.

Figure 4.186 shows a liquid flowing through a tube at the rate of $0.1 m^{3} / s$ . The tube is branched into semicircular tubes of cross-sectional area $A / 3$ and $2 A / 3$ . The velocity of liquid at $Q$ is (the cross section of the main tube is $A = 10^{- 2} m^{2}$ and $v_{p} = 20 m / s)$

The correct option is A $5 m / s$
Total flow $Q_{p} + Q_{q}$ (Parallel Arrangement)
$0.1 = A_{p} . V_{p} + A_{q} . V_{q}$ $(Q = A V)$
$0.1 = \frac{A}{3} \times 20 + \frac{2 A}{3} \times V_{q}$
$0.1 = \frac{10^{- 2}}{3} \times 20 + \frac{2 \times 10^{- 2}}{3} \times V_{q}$
$∴ V_{q} = 5 m / s .$