Question

Figure 4.191 shown water filled in a symmetrical container. Four pistons of equal area $A$ are used at the four openings to keep the water in equilibrium. Now an additional force $F$ is applied at each piston. The increase in the pressure at the center of the container due to this addition is

• A. $\frac{F}{A}$
• B. $\frac{2F}{A}$
• C. $\frac{4F}{A}$
• D. $0$

Answer 1

Answer: (A)

$\frac{F}{A}$

As at each piston additional force $F$ is introduced so change in pressure will be the net additional force upon total area upon which it acts:

$\Delta P=\frac{\Delta F}{Totalarea}$

$=\frac{4F}{4A}=\frac{F}{A}$

so, net increase in pressure at cenftre $=\frac{F}{A}$