Question

Figure $ABCD$ is a trapezoid with area $50$ square units. If the length of $\overline{AB}$ is $6$ units and the length of $\overline{BC}$ is $5$ units, what is the length of $\overline{CD}$?

• A. $4$
• B. $5$
• C. $6$
• D. $10$
• E. $14$

Answer 1

The correct option is E $14$

Area of trapezoid $=\frac{1}{2}(AB+CD)\times BC=50$ sq.units

$\Rightarrow \frac{1}{2}(6+CD)\times 5=50\Rightarrow 6+CD=\frac{50\times 2}{5}\Rightarrow CD=20-6=14$ units.