Question

Figure below shows a particle sliding on a frictionless track which terminates in a straight horizontal section. If the particle starts slipping from the point A, how far away from the end of track will the particle hit the ground? Assume, $g=10\frac{m}{s^2}$

• A. $2m$
• B. $3m$
• C. $4m$
• D. $1m$

Answer 1

The correct option is D $1m$

Using energy conservation between start and end of track

$m\times g\times l=mg\times 0.5+\frac{1}{2}m{v}^2$

$10=5+\frac{1}{2}{V}^2$

$v^2=10\Rightarrow v=\sqrt{10}\frac{m}{s}$

$y=U_{y}t+\frac{1}{2}{a}_y{t}^2$

$U_y=0\Rightarrow Y=\frac{1}{2}{a}_y{t}^2$

$0.5=\frac{1}{2}\times 10\times t^2$

$t=\frac{1}{\sqrt{10}}\text{sec}$

$x=v_{x}t\Rightarrow x=\sqrt{10}\times \frac{1}{\sqrt{10}}=1m$