Figure below shows a portion of an electric circuit with the currents in ampere and their directions. The magnitude and direction of the current in the portion PQ is:
A
0A
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B
3A from P to Q
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C
4A from Q to P
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D
6A from Q to P
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Solution
The correct option is B6A from Q to P Using Kirchoff's current law, which states that the net current in a junction is zero the let The magnitude of the current in the portion $PQ$ is x and the direction P to Q. x=−3A+1A−2A−8A+4A+2A x=−13A+7A=−6A hence,the magnitude of the current in the portion PQ is 6A and the direction from Q to P.