wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Figure below shows a small wheel fixed coaxially on a bigger one of double the radius. The system rotates about the common axis. The strings supporting A and B do not slip on the wheels. If 'x' and 'y' be the distances travelled by A and B in the same time interval, then

A
x = 2y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x = y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y = 2x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C y = 2x
Linear displacement (S) = Radius (r) × Angular displacement (θ)
Sr(if θ=constant)
Distance travelled by mass A(x)Distance travelled by mass A(y)=Radius of pulley concerned with mass A(r)Radius of pulley concerned with mass A(2r)=12y=2x.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rotational Kinematics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon