Figure given below shows the position-time graph of a particle of mass 4 kg. Find the impulse at t = 0 and t = 4 s. The motion may be considered one dimensional.

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Solution

Impulse = change in momentum
$⟹$ impulse = mass $\times$ velocity change

At t =0
$⟹$ impulse = $4 \times (\frac{3}{4} - 0)$
$⟹$ impulse = $3 N s$

At t=4s
$⟹$ impulse = $4 \times (0 - \frac{3}{4})$
$⟹$ impulse = $- 3 N s$

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Figure given below shows the position-time graph of a particle of mass 4 kg. Find the impulse at t = 0 and t = 4 s. The motion may be considered one dimensional.

Impulse = change in momentum⟹ impulse = mass × velocity changeAt t =0⟹ impulse = 4×(34−0)⟹ impulse = 3NsAt t=4s⟹ impulse = 4×(0−34)⟹ impulse = −3Ns

Impulse = change in momentum
$⟹$ impulse = mass $\times$ velocity change

At t =0
$⟹$ impulse = $4 \times (\frac{3}{4} - 0)$
$⟹$ impulse = $3 N s$

At t=4s
$⟹$ impulse = $4 \times (0 - \frac{3}{4})$
$⟹$ impulse = $- 3 N s$