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Byju's Answer

Standard XII

Physics

Current Density Vector

Figure given ...

Question

Figure given below shows three possibilities for the potential at two points, $A$ and $B$ .
In each case, the same positive charge is moved from $A$ to $B$ . The work done in the positive case will be maximum is:-

Case 1

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Case 2

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Case 3

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In all three cases

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Solution

The correct option is B Case 2

Work done $=$ Case $- 1$
$(150 - 50) V = 100 V$
Case 2
$W = (40 + 40) = 80 V$
Case 3
$W = - 20 - 80 = - 100 V$
Hence less voltage is more work done
Hence case $2$ .
will be maximum and positive.

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Figure given below shows three possibilities for the potential at two points, A and B. In each case, the same positive charge is moved from A to B. The work done in the positive case will be maximum is:-

The correct option is B Case 2Work done = Case −1 (150−50)V=100VCase 2W=(40+40)=80VCase 3W=−20−80=−100VHence less voltage is more work doneHence case 2.will be maximum and positive.

Figure given below shows three possibilities for the potential at two points, $A$ and $B$ .
In each case, the same positive charge is moved from $A$ to $B$ . The work done in the positive case will be maximum is:-

The correct option is B Case 2

Work done $=$ Case $- 1$
$(150 - 50) V = 100 V$
Case 2
$W = (40 + 40) = 80 V$
Case 3
$W = - 20 - 80 = - 100 V$
Hence less voltage is more work done
Hence case $2$ .
will be maximum and positive.