wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Figure I shows a 4-bit ripple carry adder realized using full adders and Figure II shows the circuit of a full-adder (FA). The propagation delay of the XOR, AND and OR gates in Figure II are 20 ns, 15 ns and 10 ns, respectively. Assume all the inputs to the 4-bit adder are initially reset to 0.

Figure I:


Figure II:



At t= 0, the inputs to the 4-bit adder are changed to X3X2X1X0=1100,Y3Y2Y1Y0=0100 and Z0=1. The output of the ripple carry adder will be stable at t (in ns) =



Open in App
Solution

In this question inputs to be added are :
X3X2X1X0=1100
Y3Y2Y1Y0=0100 and Z0=1
For this combination of addition, total minimum delay depends on the addition of most-significant two bits (since least significant two bits are zeros they do not cause any change in Z1and Z2). So, in the process of addition of given two digits, waveforms at Z1and Z2 become stable at t = 0 itself.


In the above diagram, the waveform at A and B become stable at t = 0 itself, as the applied input combinations do not cause any change. So, for the given combination of inputs, outputs will settle at t = 50 ns.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parallel Adder (Ripple Carry Adder)
OTHER
Watch in App
Join BYJU'S Learning Program
CrossIcon