Figure out the solutions of equation.
$3 x^{2} - 2 x - 1 = 0$

\frac{- 1}{3} & - 1

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3 & \frac{1}{3}

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\frac{+ 1}{3} & + 1

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\frac{- 1}{3} & 1

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Solution

The correct option is D $\frac{- 1}{3} & 1$
$3 x^{2} - 2 x - 1 = 0$
$(3 x + 1) (x - 1) = 0$
$x = 1 & x = \frac{- 1}{3}$

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3 x^{2} + 2 x - 1 = 0

\frac{1}{3}

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