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v-t Graph

Figure repres...

Question

Figure represents the displacement-time graph of motion of two cars A and B. Find the velocities of car A and car B.

v_{A} = 20 k m h^{- 1}, v_{B} = 10 k m h^{- 1}

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v_{A} = 10 k m h^{- 1}, v_{B} = 20 k m h^{- 1}

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v_{A} = 20 k m h^{- 1}, v_{B} = 40 k m h^{- 1}

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v_{A} = 40 k m h^{- 1}, v_{B} = 20 k m h^{- 1}

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Solution

The correct option is D $v_{A} = 40 k m h^{- 1}, v_{B} = 20 k m h^{- 1}$
For the time interval of $4 h$ ,
Displacement of car A, $D_{A} = 160 k m$
Velocity of car A, $v_{A} = \frac{160 k m}{4 h} = 40 k m / h$
Displacement of car B, $D_{B} = 120 k m - 40 k m = 80 k m$
Velocity of car B, $v_{B} = \frac{80 k m}{4 h} = 20 k m / h$

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Figure represents the displacement-time graph of motion of two cars A and B. Find the velocities of car A and car B.

The correct option is D vA=40kmh−1,vB=20kmh−1For the time interval of 4h,Displacement of car A, DA=160kmVelocity of car A, vA=160km4h=40km/hDisplacement of car B, DB=120km−40km=80kmVelocity of car B, vB=80km4h=20km/h