Figure represents two processes, a and b for a given sample of gas. Let △Q1 and △Q2 be the heat absorbed by the systems in the two cases respectively. Which of the following relations is correct?
A
△Q1=△Q2
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B
△Q1>△Q2
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C
△Q1≤△Q2
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D
△Q1<△Q2
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Solution
The correct option is B△Q1>△Q2 As the final and the initial states in both the processes are same we have no change in internal energy. Thus ΔU=0 As the work done in a process is given by the area under the PV graph, we get ΔW1>ΔW2.
Using first law we have ΔQ=ΔW+ΔU. Thus, we get ΔQ=ΔW. Thus, we have ΔQ1>ΔQ2