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Question

Figure represents two processes, a and b for a given sample of gas. Let Q1 and Q2 be the heat absorbed by the systems in the two cases respectively. Which of the following relations is correct?
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A
Q1=Q2
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B
Q1>Q2
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C
Q1Q2
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D
Q1<Q2
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Solution

The correct option is B Q1>Q2
As the final and the initial states in both the processes are same we have no change in internal energy. Thus ΔU=0 As the work done in a process is given by the area under the PV graph, we get ΔW1>ΔW2.

Using first law we have ΔQ=ΔW+ΔU.
Thus, we get ΔQ=ΔW.
Thus, we have ΔQ1>ΔQ2

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