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Standard XII

Physics

Electrical Oscillations

Figure shown ...

Question

Figure shown two equipotential surface $V_{1}$ and $V_{2}$ . The component of electric field in $x$ and $y$ direction will be:

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Solution

electric field is a conservative field so the work done does not depend upon the path taken it will only depend on the initial & find position.
$V a t p t C = \frac{k q}{r} = \frac{k q}{L}$
$V a t p t D = \frac{k q}{3 L}$
$p d$ bet $C & D = \frac{k q}{L} - \frac{k q}{3 L} = \frac{2 k q}{3 L}$
Now work done $= Q V_{p d} = \frac{2 k q Q}{3 L}$

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