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Standard XII

Physics

Inductors in Circuits

Figure shows ...

Question

Figure shows a circuit contains three identical resistors with resistance $R = 9.0 Ω$ each, two identical inductors with inductance, L = 2.0 mH each, and an ideal battery with emf $ε = 18 V$ . The current $^{'} i^{'}$ through the battery just after the switch closed is

0.2 A

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2 A

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0 A

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2 mA

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Solution

The correct option is B 2 A
At $t = 0$ , no current will flow through the inductors it will act as open circuit, so $i$ will be equal to $i_{1}$ .

Since two resistors are in open branches so current doesn't flows through it.
$i = i_{1} = \frac{ε}{R}$ $= \frac{18}{9}$ $= 2 A$

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Figure shows a circuit contains three identical resistors with resistance R=9.0Ωeach, two identical inductors with inductance, L = 2.0 mH each, and an ideal battery with emf ε=18 V. The current ′i′ through the battery just after the switch closed is

The correct option is B 2 AAt t=0, no current will flow through the inductors it will act as open circuit, so i will be equal to i1. Since two resistors are in open branches so current doesn't flows through it. i=i1=εR =189 =2 A

Figure shows a circuit contains three identical resistors with resistance $R = 9.0 Ω$ each, two identical inductors with inductance, L = 2.0 mH each, and an ideal battery with emf $ε = 18 V$ . The current $^{'} i^{'}$ through the battery just after the switch closed is

The correct option is B 2 A
At $t = 0$ , no current will flow through the inductors it will act as open circuit, so $i$ will be equal to $i_{1}$ .

Since two resistors are in open branches so current doesn't flows through it.
$i = i_{1} = \frac{ε}{R}$ $= \frac{18}{9}$ $= 2 A$