Figure shows a circuit in which three identical diode are used- Each diode has forward resistance of 20 - and infinite backward resistance- Resistors R1 - R2 - R3 - 50 - Battery voltage is 6V- The current through R3 is

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Physics

Resistivity

Figure shows ...

Question

Figure shows a circuit in which three identical diode are used. Each diode has forward resistance of 20 $Ω$ and infinite backward resistance. Resistors $R_{1}$ = $R_{2}$ = $R_{3}$ = 50 $Ω$ . Battery voltage is 6V. The current through $R_{3}$ is

50 mA

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100 mA

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60 mA

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25 mA

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Solution

The correct option is A 50 mA
Since $D_{3}$ is reverse biased, there is no current through that branch.
$∴$ Current $I = \frac{V}{R} = \frac{6}{20 + 50 + 50} =∴ 50 \times 10^{- 3} = 50 m A$

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Figure shows a circuit in which three identical diode are used. Each diode has forward resistance of 20 Ω and infinite backward resistance. Resistors R1 = R2 = R3 = 50 Ω. Battery voltage is 6V. The current through R3 is

The correct option is A 50 mASince D3 is reverse biased, there is no current through that branch.∴ Current I=VR=620+50+50=∴50×10−3=50mA

Figure shows a circuit in which three identical diode are used. Each diode has forward resistance of 20 $Ω$ and infinite backward resistance. Resistors $R_{1}$ = $R_{2}$ = $R_{3}$ = 50 $Ω$ . Battery voltage is 6V. The current through $R_{3}$ is

The correct option is A 50 mA
Since $D_{3}$ is reverse biased, there is no current through that branch.
$∴$ Current $I = \frac{V}{R} = \frac{6}{20 + 50 + 50} =∴ 50 \times 10^{- 3} = 50 m A$