Figure shows a circular loop with radius -r- The resistance of are ABC is 5- and that of ADC is 10- Magnetic field at the centre of the loop is-

344

You visited us 344 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Motional EMF in an Open Conductor

Figure shows ...

Question

Figure shows a circular loop with radius $^{'} r^{'}$ . The resistance of are $A B C$ is $5 Ω$ and that of $A D C$ is $10 Ω$ . Magnetic field at the centre of the loop is:-

\frac{μ_{0} I}{3 r} ⨂

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{μ_{0} I}{15 r} ⨂

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{μ_{0} I}{12 r} ⨀

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{μ_{0} I}{6 r} ⨀

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $\frac{μ_{0} I}{3 r} ⨂$
C $\frac{μ_{0} I}{12 r} ⨀$

Resistance $A B C = 5 Ω$ , Resistance $A D C = 10 Ω$
Current $A B C = \frac{2}{3} I$ , Current $A D C = \frac{1}{3} I$
Magnetic field due to $A B C$
$B_{1} = \frac{μ_{0} I_{A B C}}{4 R}$ out of plane.
$= \frac{μ_{0} I}{6 R}$
Similarly, $B_{2} = \frac{μ_{0} I_{A D C}}{4 R}$
$= \frac{μ_{0} I}{12 R}$
$⟹ B_{n e t} (B_{1} - B_{2}) = \frac{μ_{0} I}{12 R}$

Suggest Corrections

Similar questions

Q. A wire loop PQRSP is constructed by joining two semi-circular coils of radius

r_{1}

and

r_{2}

respectively, as shown in the figure. If the current flowing in the loop is I, then the magnetic induction at the point O is:

In the given figure MN and OP are semi-infinite wires and segment NO is a semi-ring. The magnetic field at C is (in T)

Q. In the figure shown there are two semicircles of radii

r_{1}

and

r_{2}

in which a current I is flowing. The magnetic induction at the centre O will be:

A current of I ampere flows along an infinitely long straight thin walled hollow metallic cylinder of radius r. The magnetic field at any point outside the cylinder at a distance x form the axis is

A symmetric star shaped conducting wire loop is carrying a steady state current $I$ as shown the figure. The distance between the diametrically opposite vertices of the star is $4 a$ . The magnitude of the magnetic field at the center of the loop is

Join BYJU'S Learning Program

Figure shows a circular loop with radius ′r′. The resistance of are ABC is 5Ω and that of ADC is 10Ω. Magnetic field at the centre of the loop is:-

The correct options are A μ0I3r⨂ C μ0I12r⨀Resistance ABC=5Ω, Resistance ADC=10ΩCurrent ABC=23I, Current ADC=13IMagnetic field due to ABCB1=μ0IABC4R out of plane.=μ0I6RSimilarly, B2=μ0IADC4R=μ0I12R⟹Bnet(B1−B2)=μ0I12R

Figure shows a circular loop with radius $^{'} r^{'}$ . The resistance of are $A B C$ is $5 Ω$ and that of $A D C$ is $10 Ω$ . Magnetic field at the centre of the loop is:-