Question

Figure shows a closed surface which intersects a conducting sphere. If a positive charge is placed at the point $P$, the flux of the electric field through the closed surface due to induction :

• A. will remain zero
• B. will become positive
• C. will become negative
• D. will become undefined

Answer 1

The correct option is B will become positive

All the charges are uniformly distributed on the surface of conducting sphere. Field inside the sphere is zero and field outside the sphere is directed outward from surface of sphere. Due to positive charge at P the charge distribution become non-uniform.
Here closed surface will contain some part of conducting sphere. So some positive charge will be enclosed by closed surface. According to Gauss's law, the flux of the electric field through the closed surface will become positive. $(\varphi =\frac{Q_{en}}{{ϵ}_0})$