Figure shows a copper rod moving with velocity v parallel to a long straight wire carrying current =100A. Calculate the induced emf in the rod, where v=5ms−1,a=1cm,b=100cm.
A
0.23mV
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B
0.46mV
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C
0.16mV
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D
0.32mV
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Solution
The correct option is D0.46mV forceonaparticleofunitchargeisF=vB=vμ0I2πxdW=Fdx⇒dW=vμ0I2πxdx⇒W=EMF=vμ0I2πln(ba)=5×μ0×1002πn(1001)=0.46mV