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Question

Figure shows a curve on logT and logV scale, when an ideal gas is undergoing an adibatic process. The gas is


A
Monatomic
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B
Diatomic
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C
Polyatomic
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D
Mixture of monatomic and diatomic
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Solution

The correct option is A Monatomic
For an adiabatic process, equation of state in terms of T and V is given by
TVγ1=k
Taking logarithm on both sides,
logT+(γ1)logV=logk
logT=(γ1)logV+logk
Comparing this with Y=mX+c, we get,
Slope m=(γ1)
from the data given in the graph, we can say that
(γ1)=2441
(γ1)=23
γ=53
Ideal gas is monoatomic in nature.
Thus, option (a) is the correct answer.

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