CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
135
You visited us 135 times! Enjoying our articles? Unlock Full Access!
Question

Figure shows a long current carrying wire and a rectangular loop moving with velocity v. The induced current in the loop is


A
in clockwise sense
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
in anticlockwise sense
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
in clockwise, then anti-clockwise sense
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D zero
We know that the magnetic field due to a long current carrying wire is inversely proportional to the perpendicular distance from the wire.

In the given case, the loop is moving parallel to the wire.

Therefore, the perpendicular distance of the loop is constant from the wire and hence, the flux linked with the loop is also constant.

So, there will be no induced emf and current in the loop.

Hence, option (D) is the correct answer.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric motor
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon