The correct option is
D The induced charges appearing on
S1 are non-uniformly distributed.
Electric field inside a cavity in a conductor is always zero. Even if the conductor is charged or charges are induced on a neutral conductor by an external field, all charges reside only on the surface of the conductor. Hence, any cavity of any shape and size is always shielded from outer electrical influence.
So, the electric field due to induced charges on
S1 is directed towards
S1 and electric field due to charge
Q at point
P is also directed towards
S1. Therefore, Net electric field at point
P is Non-zero, and influence of charges
S2 at point
P will be zero due to electrostatic shielding.
Due to the induction process, the
+Q charge placed in the cavity induces
−Q charge on the surface
S1. Since the surface
S1 is non-uniform and charge is also not placed symmetrically, so the induced charge will be non-uniformly distributed.
Since the conductor is electrically neutral,
+Q charge appears on
S2. The surface is uniform, so the induced charge on it will be uniformly distributed.
Hence, option (a), (c) and (d) are correct statements.