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Question

Figure shows a parabolic graph between T and 1V (T= temperature, V= volume) for a mixture of gases undergoing an adiabatic process. The ratio of rms velocity of molecules and speed of sound in the mixture of gases at the same temperature is given by n. Find n.


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Solution

Let the relation between T and 1V be
T=K(1V)n
2T0=K(4V0)n and T0=K(1V0)n
2=4nn=12
Therefore T=K(1V)12 or TV1/2=constant
But for adiabatic process, TVγ1=constantγ1=12 or γ=32
VmixVsound=3γ=33/2=2

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