Figure shows a particle starting from point A, travelling upto B with a speed s, then upto point C with a speed 2s and finally upto A with a speed of 3s. Find its average speed.
A
1.2s
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B
1.8s
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C
2.4s
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D
3s
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Solution
The correct option is B1.8s
Angle ∠AOB=90∘=π/2, ∠BOC=120∘=2π/3
∴∠AOC=2π−(π2+2π3)=5π6
t1=ABs=π2Rs,t2=BC2s=2π3R2s,t3=CA3s=5πR63s
Average Speed =2πRt1+t2+ts=2πRπR2s+πR3s+5πR18s=2×18s20=1.8s