wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Figure shows a small block of mass 'm' which is started with a speed 'v' on the horizontal part of the bigger block of mass 'M' placed on a horizontal floor. The curved part of the surface shown is semicircular. All the surfaces are frictionless. Find the speed of the bigger block when the smaller block reaches the point A of the surface.


A

towards left

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

towards left

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

towards left

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

towards left

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

towards left


A small block of mass m which is started with a velocity V on the horizontal part of the bigger block of mass M placed on a horizontal floor.

Since the small body of mass m is started with a velocity V in the horizontal direction, so the total initial momentum at the initial position in the horizontal direction will remain same as the total final momentum at the point A on the bigger block in the horizontal direction.

From L.C.M m:


mv+M×O=(m+M)vv=mvM+m


flag
Suggest Corrections
thumbs-up
9
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Why Is the Center of Mass the Real Boss?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon