wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Figure shows a uniform disc of radius R from which a hole of radius R/2 has been cut out from centre and filled with a material of twice the density of the original disc. Find the change in position of COM.


A
COM will shift R/2 distance towards right
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
COM will shift R/2 towards left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
COM will shift 2R/3 distance towards right
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Position of COM will not change
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Position of COM will not change
Initial coordinates of COM of the disc are (0,0). When the hole is cut out and filled with material of twice the density, the coordinates of COM of hole and the new material are both (0,0)
Therefore, coordinates of resulting disc will not change as coordinates of COM of both (hole and new disc) are at the same point (0,0).
Hence, COM of the resulting disc will be at origin (0,0)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon