Figure shows a uniform rod of mass $3 k g$ and of length $30 c m$ . The strings shown in figure are pulled by constant forces of $20 N$ and $32 N$ . The acceleration of the rod is:

2 m / s^{2}

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3 m / s^{2}

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4 m / s^{2}

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6 m / s^{2}

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Solution

The correct option is A $4 m / s^{2}$
We just have to calculate resultant force acting on the block and divide it by mass $m$ of the block.
Therefore, the resultant force $F = 32 N - 20 N = 12 N$
So, $a = \frac{F}{m} = \frac{12}{3} = 4 m / s^{2}$

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Similar questions

Q. Figure shows a uniform rod of length

30 c m

having mass of

30 k g

. The strings shown in the figure are pulled by constant forces of

20 N

and

32 N

. Find the force exerted by the

20 c m

part of the rod on the

10 c m

part. All the surfaces are smooth and the strings and the pulley are light

In Figure shows a uniform rod of length 30 cm having a mass of 3.0 kg. The strings shown in the figure are pulled by constant forces of 20 N and 32 N. Find the force exerted by the 20 cm part of the rod on the 10 cm part. All the surfaces are smooth and the strings and the pulleys are light.