Question

Figure shows a uniformly charged hemispherical shell. The direction of electric field at point p, that is off-centre (but in the plane of the largest circle of the hemisphere), will be along

• A. pa
• B. pb
• C. pc
• D. pd

Answer 1

The correct option is A pa

Electric potential at point $P$

${\varphi }_E=EA\cos \phi$

$=EA$

$=E\left(\pi r^2\right)(\because E=P)$

$=\rho a$ ($\because$ $a=$ area of hemisphere)