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Standard VII

Physics

Law of Conservation of Energy

Figure shows ...

Question

Figure shows a wheel barrow of mass $15 k g$ carrying a load of $30 k g f$ with its centre of gravity at $A$ . The points $B$ and $C$ are the centre of wheel and tip of the handle such that the horizontal distance $A B = 20 c m$ and $A C = 40 c m$ . What is the mechanical advantage?

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Solution

The correct option is D $3$
Load Arm = Distance of load from Fulcrum $= A B = 20 c m$
Effort Arm = Distance from effort applied to Fulcrum $= A B + A C = 20 + 40 = 60 c m$
Mechanical Advantage $= \frac{Effort Arm}{Load Arm}$
$\Rightarrow \frac{60}{20} = 3$

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Figure shows a wheel barrow of mass 15 kg carrying a load of 30kgf with its centre of gravity at A. The points B and C are the centre of wheel and tip of the handle such that the horizontal distance AB=20 cm and AC=40 cm. What is the mechanical advantage?

The correct option is D 3Load Arm = Distance of load from Fulcrum =AB=20cmEffort Arm = Distance from effort applied to Fulcrum =AB+AC=20+40=60cmMechanical Advantage =Effort ArmLoad Arm⇒6020=3

Figure shows a wheel barrow of mass $15 k g$ carrying a load of $30 k g f$ with its centre of gravity at $A$ . The points $B$ and $C$ are the centre of wheel and tip of the handle such that the horizontal distance $A B = 20 c m$ and $A C = 40 c m$ . What is the mechanical advantage?

The correct option is D $3$
Load Arm = Distance of load from Fulcrum $= A B = 20 c m$
Effort Arm = Distance from effort applied to Fulcrum $= A B + A C = 20 + 40 = 60 c m$
Mechanical Advantage $= \frac{Effort Arm}{Load Arm}$
$\Rightarrow \frac{60}{20} = 3$