MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oscillations of a Simple Pendulum

Figure shows ...

Question

Question 7

Figure shows an oscillating pendulum.

Time taken by the bob to move from A to C is $t_{1}$ and from C to O is $t_{2}$ . The time period of this simple pendulum is

(a) $(t_{1} + t_{2})$

(b) $2 (t_{1} + t_{2})$

(c) $3 (t_{1} + t_{2})$

(d) $4 (t_{1} + t_{2})$

Open in App

Solution

A to O is equal to the $\frac{1}{4}$ th of the oscillation. Hence, time period = 4 times (A to C + C to O) = $4 (t_{1} + t_{2})$

Suggest Corrections

thumbs-up

77

Similar questions

Q. Figure shows an oscillating pendulum.

Time taken by the bob to move from A to C is

t_{1}

and from C to O is

t_{2}

. The time period of this simple pendulum is

A particle executes simple harmonic motion between x = -A and x=+ A. The time taken for it to go from the mean position, O to $\frac{A}{2}$ is $T_{1}$ and to go from $\frac{A}{2}$ to A is $T_{2}$ . Then,

The following figure shows the elliptical path of a planet about the sun. The two shaded parts have equal areas. If $t_{1}$ , $t_{2}$ be the time taken by the planet to go from A to B and from C to D respectively.

Q. A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is

T_{1}

and to go from A/2 to A is

T_{2} .

Q. A particle executes simple harmonic motion (amplitude

= A

x = - A

x = + A

. The time taken for it to go from

0

\frac{A}{2}

T_{1}

\frac{A}{2}

A

T_{2}

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Oscillations of a Simple Pendulum

Standard VII Physics

Join BYJU'S Learning Program

CrossIcon