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Oscillations of a Simple Pendulum

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Question

Question 7

Figure shows an oscillating pendulum.

Time taken by the bob to move from A to C is $t_{1}$ and from C to O is $t_{2}$ . The time period of this simple pendulum is

(a) $(t_{1} + t_{2})$

(b) $2 (t_{1} + t_{2})$

(c) $3 (t_{1} + t_{2})$

(d) $4 (t_{1} + t_{2})$

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Solution

A to O is equal to the $\frac{1}{4}$ th of the oscillation. Hence, time period = 4 times (A to C + C to O) = $4 (t_{1} + t_{2})$

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Oscillations of a Simple Pendulum

Standard VII Physics

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