MyQuestionIcon

4

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Visualising Potential

Figure shows ...

Question

Figure shows five charged lumps of plastic and an electrically neutral coin. The cross section of Gaussian surface $S$ is indicated. Assuming $q_{1} = q_{4} = 3.1 n C, q_{2} = q_{5} - 5.9 n C, q_{3} = - 3.1 n C$ , the net electric flux through the surface is :

A

- 666 N m^{2} / C^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

+ 666 N m^{2} / C^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

- 360 N m^{2} / C^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

+ 360 N m^{2} / C^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 666 N m^{2} / C^{- 1}$
$ϕ = \frac{\sum q}{\in_{0}} = \frac{- 5.9 \times 10^{- 9}}{8.85 \times 10^{- 12}} = - 670 N m^{2} / C$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Assertion :Four point charges

q_{1}

q_{2}

q_{3}

q_{4}

are as shown in figure. The flux over the shown Gaussian surface depends only on charges

q_{1}

q_{2}

. Reason: Electric field at all points on Gaussian surface depends only charges

q_{1}

q_{2}

.

Q. The three small sphere as shown in fig. carry charges

q_{1} = 4 n C, q_{2} = - 7.8 n C

q_{3} = 2.4 n C

. Find out the magnitude of the net electric flux in

N m^{2} / C

S_{2}

surface shown in cross section in the figure.

Q. Three charges of

q_{1} = 1 \times 10^{- 6} C

q_{2} = 2 \times 10^{- 6} C

q_{3} = - 3 \times 10^{- 6} C

have been placed as shown. Then, the net electric flux will be maximum for the surface

Q. Fig. shows four charges

q_{1}, q_{2}, q_{3}

q_{4}

fixed in space. Then the total flux of the electric field through a closed surface S, due to all the charges, is:

(A)

: Four point charges

q_{1}, q_{2}, q_{3}

q_{4}

are as shown in figure. The flux over the shown gaussian surface depends only on charges

q_{1}

q_{2}

(R)

: Electric field at all points on gaussian surface is depends only on charges

q_{1}

q_{2}

Select the most appropriate answer from the options given below

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electric Potential as a Property of Space

PHYSICS

Watch in App

explore_more_icon

Explore more

Visualising Potential

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon