Figure shows graphs of pressure vs density for an ideal gas at two temperatures T1 and T2-a T1-T2b T1-T2c T1-T2d Any of the three is possible-

The straight line T1 has greater slope than T2. This means nbsp;Pρ nbsp;ratio is greater for T1 than T2. Now, rms velocity of a gas is given by 3Pρ. This ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Compressibility Factor

Figure shows ...

Question

Figure shows graphs of pressure vs density for an ideal gas at two temperatures T₁ and T₂.
(a) T₁ > T₂
(b) T₁ = T₂
(c) T₁ < T₂
(d) Any of the three is possible.

Open in App

Solution

The straight line T₁ has greater slope than T₂. This means $\frac{P}{ρ}$ ratio is greater for T₁ than T₂. Now, rms velocity of a gas is given by $\sqrt{\frac{3 P}{ρ}}$ . This means rms velocity of gas with T₁ molecules is greater than T₂ molecules. Again, gas with higher temperature has higher rms velocity.

So, T₁ > T₂.

Thus, (a) is the correct answer.

Suggest Corrections

Similar questions

The figure shows graphs of pressure versus density for an ideal gas at two temperature $T_{1} a n d T_{2}$ which is correct?

The figure shows pressure versus density graph for an ideal gas at two temperature $T_{1}$ and $T_{2}$ :

Q. Figure show graphs of pressure vs density for an ideal gas at two temperatures

T_{1}

and

T_{2}

What can be inferred about

T_{1}

and

T_{2}

Q. Figure 24-Q1 shows graphs of pressure vs density for an ideal gas at two temperatures

T_{1}

and

T_{2}

Q. Figure shows graphs of pressure versus density for an ideal gas at two temperature

T_{1}

and

T_{2}

. Which is correct?

Join BYJU'S Learning Program

Figure shows graphs of pressure vs density for an ideal gas at two temperatures T1 and T2. (a) T1 > T2 (b) T1 = T2 (c) T1 < T2 (d) Any of the three is possible.

Figure shows graphs of pressure vs density for an ideal gas at two temperatures T₁ and T₂.
(a) T₁ > T₂
(b) T₁ = T₂
(c) T₁ < T₂
(d) Any of the three is possible.