Question

Figure shows the displacement of a body at different times. Calculate the average velocity during the time interval $5$ s to $9$ s. [Hint: From $5$ s to $9$ s, displacement $=7$ m$-3$ m$=4$ m]

Answer 1

Given,
Time of journey, $t=9-5=4\text{s}$
The displacement of the body during the time interval $5\text{s}$ to $9\text{s},S=4\text{m}$
We have,
$\text{Average velocity}=\frac{\text{total displacement}}{\text{time taken}}{V}_{\text{avg}}=\frac{4m}{4\text{s}}=1\text{ms}{\text{s}}^{-1}$
Hence, average velocity for interval $5\text{s}$ to $9\text{s}$ is $1m{s}^{-1}$.