Question

Figure shows the displacement - time graphs of two simple harmonic motions I and II. From the graph it follows that the

• A. curve I has frequency as that of curve II.
• B. curve I has frequency twice that of curve II.
• C. curve I has frequency half that of curve II
• D. curve I has frequency four times that of curve II.

Answer 1

The correct option is C curve I has frequency half that of curve II

Time period, $T_{=}8s$, Frequency, $v_1=\frac{1}{T_1}=\frac{1}{8}$Hz.

For curve II,
Time period, $T_2=4s$, Frequency, $v_2=\frac{1}{T_2}=\frac{1}{4}$Hz
Their corresponding ratio
$\frac{v_1}{v_2}=\frac{1}{2}or{v}_1=\frac{1}{2}{v}_2$.