Question

Figure shows the Distance-Time graph of an object. Calculate the following:

(i) Average speed in the first 6 s.

(ii) Distance travelled at the end of 10 s.

(iii) Speed at t = 2 s, and at t = 6 s [5 MARKS]

Answer 1

Part 1: 1 Mark
Part 2: 1 Mark
Part 3: 3 Mark



So looking at the above distance-time graph we can find:
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(i) Average speed at 6 s,
$v=\frac{100}{6}=16.67m/s$

(ii) Distance travelled at the end of 10 s = 100 m

(iii) Speed at $t=2s$

Speed $v_1$ = $\frac{40}{2}$ = $20m/s$

Speed at 6 s,
$v_2=\frac{100}{6}=16.67m/s$