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Standard XII

Physics

Kepler's Law

Figure shows ...

Question

Figure shows the elliptical path of a planet around the sun. The two shaded parts have equal areas. If $t_{1}$ and $t_{2}$ be the time taken by the planet to go from $a$ to $b$ and from $c$ to $d$ respectively, then

t_{1} < t_{2}

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t_{1} = t_{2}

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t_{1} > t_{2}

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Insufficient information to deduce the relation between

t_{1}

and

t_{2}

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Solution

The correct option is D $t_{1} = t_{2}$
When a planet revolves around the sun, areal velocity is constant.
Since areas are equal,
$\frac{d ¯ A}{d t} =$ constant
or $t_{1} = t_{2}$

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Q. Figure (11-Q2) shows the elliptical path of a planet about the sun. The two shaded parts have equal area. If t₁ and t₂ be the time taken by the planet to go from a to b and from c to d respectively,
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(c) t₁ > t₂
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Figure

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Q. The following figure shows the elliptical path of a planet around the sun at point

O

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Figure shows the elliptical path of a planet around the sun. The two shaded parts have equal areas. If t1 and t2 be the time taken by the planet to go from a to b and from c to d respectively, then

The correct option is D t1=t2When a planet revolves around the sun, areal velocity is constant.Since areas are equal,d¯Adt=constantor t1=t2

Figure shows the elliptical path of a planet around the sun. The two shaded parts have equal areas. If $t_{1}$ and $t_{2}$ be the time taken by the planet to go from $a$ to $b$ and from $c$ to $d$ respectively, then

The correct option is D $t_{1} = t_{2}$
When a planet revolves around the sun, areal velocity is constant.
Since areas are equal,
$\frac{d ¯ A}{d t} =$ constant
or $t_{1} = t_{2}$