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Question

Figure shows the intensity-wavelength relations of X-rays coming from two different Coolidge tubes. The solid curve represents the relation for the tube A in which the potential difference between the target and the filament is VA and the atomic number of the target material is ZA. These quantities are VB and ZB for the other tube. Then

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A
VA>VB,ZA>ZB
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B
VA>VB,ZA<ZB
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C
VA<VB,ZA>ZB
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D
VA<VB,ZA<ZB
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Solution

The correct option is B VA>VB,ZA<ZB
λmin of A<λmin of B
so VA>VB
also λKα,A>λKα,B
so ZB>ZA

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