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Byju's Answer

Standard IX

Physics

Universal Law of Gravitation

Figure shows ...

Question

Figure shows the motion of a planet around the Sun S in an elliptical orbit with the Sun at the focus. The shaded areas A and B are also shown in the figure which can be assumed to be equal. If $t_{1}$ and $t_{2}$ represent the time taken for the planet to move from a to b and c to d, respectively, then.

t_{1} < t_{2}

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t_{1} > t_{2}

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t_{1} = t_{2}

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From the given information the relation between

t_{1}

and

t_{2}

cannot be determined.

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Solution

The correct option is C $t_{1} = t_{2}$
Kepler's second law of area: A radius vector joining any planet to the Sun sweeps out equal area in equal length of time.
By second law, area swept is same and hence time is same i.e. $t_{1} = t_{2}$

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Figure shows the motion of a planet around the Sun S in an elliptical orbit with the Sun at the focus. The shaded areas A and B are also shown in the figure which can be assumed to be equal. If t1 and t2 represent the time taken for the planet to move from a to b and c to d, respectively, then.

The correct option is C t1=t2Kepler's second law of area: A radius vector joining any planet to the Sun sweeps out equal area in equal length of time. By second law, area swept is same and hence time is same i.e. t1=t2

The correct option is C $t_{1} = t_{2}$
Kepler's second law of area: A radius vector joining any planet to the Sun sweeps out equal area in equal length of time.
By second law, area swept is same and hence time is same i.e. $t_{1} = t_{2}$