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Distance Time Graph

Figure shows ...

Question

Figure shows the position-time graph of a particle of mass 4 kg. Let the force on the particle for t < 0,0<t<4,0 < 4 s, be $F_{1}, F_{2}$ and $F_{3}$ respectively. Then

F_{1} = F_{2} = F_{3} = 0

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F_{1} > F_{2} = F_{3}

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F_{1} > F_{2} > F_{3}

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F_{1} < F_{2} < F_{3}

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Solution

The correct option is A $F_{1} = F_{2} = F_{3} = 0$
For t < 0 and t > 4 s, the position of the particle is not changing i.e. the particle is at rest. So no force is acting on the particle at these intervals.
For 0< t < 4 s, the positions of the particle is continuously changing. As the position-time graph is a straight line, the motion of the particle is uniform, so acceleration, a=0. Hence no force acts on the particle during this interval also.

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Figure shows the position-time graph of a particle of mass 4 kg. Let the force on the particle for t < 0,0<t<4,0 < 4 s, be F1,F2 and F3 respectively. Then

Figure shows the position-time graph of a particle of mass 4 kg. Let the force on the particle for t < 0,0<t<4,0 < 4 s, be $F_{1}, F_{2}$ and $F_{3}$ respectively. Then