Figure shows the shape of part of a long string in which transverse waves are produced by attaching one end of the string to tuning fork of frequency 250 Hz. What is the velocity of the waves?

1.0 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.5 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.0 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1.0 m s^{- 1}$
f = 250 Hz
$λ = 0.5 - 0.1$
= 0.4 cm
$v = f λ$
$= 250 \times 0.4 \times 10^{- 2}$
$= 1 m s^{- 1}$

Suggest Corrections

Similar questions

The given figure shows the shape of part of a long string in which transverse waves are produced by attaching one end of the string to tuning fork of frequency 250 Hz. What is the velocity of the waves?

The figure showed the shape of part of a long string in which transverse waves are produced by attaching one end of the string to tuning fork of frequency

250 H z

. What is the velocity of the waves?

Q. Transverse waves are produced in a long string by attaching its free end to a vibrating tuning fork. Figure shows the shape of a part of the string. The points in phase are

A tuning fork of frequency 440 Hz is attached to a long string of linear mass density $0.01 k g m^{- 1}$ kept under a tension of 49 N. The fork produces transverse waves of amplitude 0.50 mm on the string. (a) Find the wave speed and the wavelength of the waves. (b) Find the maximum speed and acceleration of a particle of the string. (c) At what average rate is the tuning fork tranmitting energy to the string ?

Join BYJU'S Learning Program

Figure shows the shape of part of a long string in which transverse waves are produced by attaching one end of the string to tuning fork of frequency 250 Hz. What is the velocity of the waves?

The correct option is A 1.0 ms−1f = 250 Hz λ=0.5−0.1 = 0.4 cm v=fλ =250×0.4×10−2 =1 ms−1

The correct option is A $1.0 m s^{- 1}$
f = 250 Hz
$λ = 0.5 - 0.1$
= 0.4 cm
$v = f λ$
$= 250 \times 0.4 \times 10^{- 2}$
$= 1 m s^{- 1}$