Question

Figure shows the temperature variation when heat is added continuously to a specimen of ice $\left(10\text{g}\right)$ at $-{40}^{\circ }\text{C}$ at constant rate. (Specific heat of ice $=0.53{\text{cal/g}}^{\circ }\text{C}$ and $L_{\text{ice}}=80\text{cal/g},L_{\text{water}}=540\text{cal/g)}$

$\begin{array}{cc}\text{Column - I}& \text{Column - II}\\ \left(A\right)\text{Value of}{Q}_1\text{(in cal)}& \left(P\right)800\\ \left(B\right)\text{Value of}{Q}_2\text{(in cal)}& \left(Q\right)1000\\ \left(C\right)\text{Value of}{Q}_3\text{(in cal)}& \left(R\right)5400\\ \left(D\right)\text{Value of}{Q}_4\text{(in cal)}& \left(S\right)212\\ & \left(T\right)900\end{array}$

• A. $A\to S;B\to P;C\to Q;D\to T$
• B. $A\to P;B\to S;C\to Q;D\to R$
• C. $A\to P;B\to S;C\to R;D\to Q$
• D. $A\to S;B\to P;C\to Q;D\to R$

Answer 1

The correct option is D $A\to S;B\to P;C\to Q;D\to R$

$Q_1=\text{m}{S}_{ice}\Delta T=10\times 0.53\times 40=212\to \left(S\right)$
$Q_2=m{L}_{ice}=10\times 80\to \left(P\right)$
$Q_3=\text{m}{S}_{water}\Delta T=10\times 1\times 100=1000\to \left(Q\right)$
$Q_4=\text{m}{L}_{water}=10\times 540=5400\to \left(R\right)$