wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Figure shows the vertical section of a frictionless surface. A block of mass 2kg is released from rest from position A. Its K.E as it reaches position C is (g = 10 m/s2)

A
140 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
180 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
120 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
280 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 140 J
Applying WET from A to C,
KA+UA=KC+UC
0+mg(14)=KC+mg(7)
KC=7mg
=7×2×10
=140J

flag
Suggest Corrections
thumbs-up
28
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon