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Properties of Field Lines

Figure shows ...

Question

Figure shows two equipotential surface $V_{1}$ and $V_{2}$ . The component of electric field in $x$ and $y$ direction will be

E_{x} i

and

E_{x} j

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- E_{x} i

and

E_{x} j

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E_{x} i

and

- E_{x} j

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- E_{x} i

and

- E_{x} j

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is B $- E_{x} i$ and $E_{x} j$
$\begin{matrix} \to E = - E_{x} ˆ i + R_{y} ˆ j ∵ B o t h E x & E y a r e e q u a l ∴ \to E = - E_{x} ˆ i + R_{y} ˆ j ∴ O p t i o n (B) i s c o r r e c t . \end{matrix}$

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