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Question

# Figure shows two long conducting wires placed at right angles. They carry current as indicated. Assume that I A current in a long wire produces magnetic field B at a distance d from the wire. The strength and direction of field at a point x marked in the figure will be

A
3B into the plane of the paper
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B
B into the plane of the paper
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C
B out of the plane of the paper
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D
3B out of the plane of the paper
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Solution

## The correct option is A 3B into the plane of the paperGiven: current in horizontal wire,I1=1A in +xdirn current in vertical wire,I2=2A in −ydirnmagnetic field at x due to horizontal wire is,B1=B into the plane of paperTo find: magnetic field at x=?Solution: As we know that,magnetic field by a long conducting wire at distance a is, B=μ0I2πa So, Due to horizontal wire :B1=μ0I12πd ==>B1=μ02πd=B, into the plane of paper and Due to vertical wire :B2=μ0I22πd ==>B2=2μ02πd=2B, into the plane of paper Net magnetic field at x:B′=B1+B2B′=B+2BB′=3B, into the plane of paperhence,The correct opt: A

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