The correct options are
A Focal length of the lens is equal to intercept on v−axis
B Focal length of the lens is equal to inverse of slope of the line
C Magnitude of intercept on m-axis is equal to unity
1v−1u=1f
1−vu=vf
Since m is positive in the given figure, therefore m represents magnitude of the magnification. In fact, if a real image is formed by a convex len, then the image and object will be on opposite sides of the lens. It means, if v is positive, then u will be negative. Therefore,
m=∣∣vu∣∣=−vu
Hence, Eq. (i) becomes
m=vf−1....(ii)
It means, the graph between m and v will be a straight line having intercept −1 and m−axis and slope of the line tanθ is equal to (1/f). Hence, option (b) and (c) are correct. Putting m=0 in Eq. (ii), v=f. Hence, (a) is also correct. Obviously, (d) is wrong.