FigureA particle starts from a point A and travels along the solid curve shown in figure (3−E7). Find approximately the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B.

Open in App

Solution

At position B , the instantaneous velocity of the particle has the direction along $\vec{BC}$ .

Average velocity between A and B, $V_{a v} = \frac{Displacement}{Time}$ $= (\frac{\vec{AB}}{t})$
We can see that $\vec{AB}$ and $\vec{BC}$ are in the same direction. The point is B (5 m, 3 m).

Suggest Corrections

Similar questions

Q. A particle starts from a point A and travels along the solid curve shown in figure. Find approximately the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B.

A particle starts from a point A and travels along the sold curve shown in figure. Find approximaterly the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B

Q. The trajectory of a particle moving in large field is as shown in the figure. The coordinates of a position A are (0, 2). The coordinates of another point at which the instantaneous velocity is same as the average velocity between the points are :

A particle starts its motion from point A in the positive x direction in such a way that after every t sec it is at a distance of $t^{2}$ from the starting point. Find its instantaneous velocity at $t = 4^{t h}$ sec also the rate at which velocity changes.

Q. A particle starts moving such that position with respect to origin O varies with time t as x{t} = 2t m. Find
(a) average velocity between (i) t = 0 & t = 1s (ii) t = 0 & t = 2s (iii) t = 1s & t = 2s
(b) instantaneous velocity at general time t.

Join BYJU'S Learning Program

FigureA particle starts from a point A and travels along the solid curve shown in figure (3−E7). Find approximately the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B.

At position B , the instantaneous velocity of the particle has the direction along BC→. Average velocity between A and B, Vav=DisplacementTime=AB→t We can see that AB→ and BC→ are in the same direction. The point is B (5 m, 3 m).

At position B , the instantaneous velocity of the particle has the direction along $\vec{BC}$ .

Average velocity between A and B, $V_{a v} = \frac{Displacement}{Time}$ $= (\frac{\vec{AB}}{t})$
We can see that $\vec{AB}$ and $\vec{BC}$ are in the same direction. The point is B (5 m, 3 m).