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Question

Fiind the value of each of the following:
(i) 3−1 + 4−1
(ii) (30 + 4−1) × 22
(iii) (3−1 + 4−1 + 5−1)0
(iv) 13-1-14-1-1

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Solution

(i) We know from the property of powers that for every natural number a, a−1 = 1/a. Then:
3^{-1}+4^{-1}=frac{1}{3}+frac{1}{4} ---> (a−1 = 1/a)
=frac{4+3}{12}
=frac{7}{12}

(ii) We know from the property of powers that for every natural number a, a−1 = 1/a.
Moreover, a0 is 1 for every natural number a not equal to 0. Then:

30+4-1×22=1+14×4 as, a-1=1a; a0=1=54×4=5


(iii) We know from the property of powers that for every natural number a, a−1 = 1/a.
Moreover, a0 is 1 for every natural number a not equal to 0. Then:
(3-1+4-1+5-1)=1 ---> (Ignore the expression inside the bracket and use a0 = 1 immediately.)

(iv) We know from the property of powers that for every natural number a, a−1 = 1/a. Then:
left (left (frac{1}{3} right )^{-1}-left (frac{1}{4} right )^{-1} right )^{-1}=left ( 3-4 right )^{-1} ---> (a−1 = 1/a)
=left ( -1 right )^{-1}
=-1 ---> (a−1 = 1/a)

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