Fill in the blank
$(3 x^{2} + 4 y) (2 x + 3 y) = □$

Open in App

Solution

$(3 x^{2} + 4 y) (2 x + 3 y)$
$= 6 x^{3} + 9 x^{2} y + 8 x y + 12 y^{2}$
$= 6 x^{3} + 12 y^{2} + x y (9 x + 8)$

Suggest Corrections

Similar questions

{(2 x - \frac{1}{3 x})}^{2}

{(3 x^{2} + 5 y)}^{2}

(\sqrt{2 x} - 3 y) (\sqrt{2 x} + 3 y)

{(\frac{1}{4} a - \frac{1}{2} b + 1)}^{2}

38 x^{3} y^{2} z \div 19 x y^{2}

(3 x^{2} + 4 y) \times (2 x + 3 y)

If x + y + z = xyz. Then

$\frac{3 x - x^{3}}{1 - 3 x^{2}}$ + $\frac{3 y - y^{3}}{1 - 3 y^{2}}$ + $\frac{3 z - z^{3}}{1 - 3 z^{3}}$ =

6 x^{2} + 3 y - 2 z

3 x^{2} - y

Join BYJU'S Learning Program