Question

Fill in the blank: $\frac{4}{7}(\frac{7}{15}-\frac{21}{4})=\frac{4}{7}\times \frac{7}{15}-....\times \frac{4}{7}$

• A. $\frac{4}{7}$
• B. $\frac{21}{4}$
• C. $\frac{-21}{4}$
• D. $\frac{7}{15}$

Answer 1

Answer: (B)

$\frac{21}{4}$

Distributive property over subtraction holds true for rational numbers.

Thus, $a(b-c)=a\times b-a\times c$

$\therefore \frac{4}{7}(\frac{7}{15}-\frac{21}{4})=\frac{4}{7}\times \frac{7}{15}-\frac{4}{7}\times \frac{21}{4}$

$=\frac{4}{7}\times \frac{7}{15}-\frac{21}{4}\times \frac{4}{7}$ ($\because$ commutative property).